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The First Pentagon Plan To Use Nuclear Weapons Against The Soviet Union Involved 66 Targets And 204 Bombs

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Title : The First Pentagon Plan To Use Nuclear Weapons Against The Soviet Union Involved 66 Targets And 204 Bombs
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The First Pentagon Plan To Use Nuclear Weapons Against The Soviet Union Involved 66 Targets And 204 Bombs


South Front: “Wipe the Soviet Union Off the Map”: Planned US Nuclear Attack against USSR

According to a secret document dated September 15, 1945, “the Pentagon had envisaged blowing up the Soviet Union with a coordinated nuclear attack directed against major urban areas.

All major cities of the Soviet Union were included in the list of 66 “strategic” targets. The tables below categorize each city in terms of area in square miles and the corresponding number of atomic bombs required to annihilate and kill the inhabitants of selected urban areas.

Six atomic bombs were to be used to destroy each of the larger cities including Moscow, Leningrad, Tashkent, Kiev, Kharkov, Odessa.

The Pentagon estimated that a total of 204 bombs would be required to “Wipe the Soviet Union off the Map”. The targets for a nuclear attack consisted of sixty-six major cities.

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WNU Editor: This Pentagon plan was dated September 15, 1945, just over a month after Hiroshima and Nagasaki were destroyed by nuclear weapons. Interestingly, the bombings used up all of America's nuclear arsenal, and (if memory serves me correctly), it would be another 6 months before the would have another nuclear weapon. So even if the U.S. wanted to wage a nuclear strike against the Soviet Union, it would be years before they would be able to do so.


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